Use the information to find and compare \Delta y and dy. Round answer to four decimal places. y = x^ {4} + 6, x = -5, \Delta x = dx = 0.01. If z = x^2 - x y + 3 y^2 and (x, y) changes from (2, -1) to (1.97, -0.95), compare the values of Delta z and dz. (Round your answer to 4 decimal plces.) Plot \frac {1} {\pi} \frac {a} {a^2 + x^2} and show Yes: Assuming f (x)= 0 if x= โˆ’1, or x =2, then one possible function for f (x) will be f (x)= (x+1)(xโˆ’2). And we are given g(x) =2xโˆ’1. If this is the case, it follows that (f โˆ˜ g)(x) =f (g(x))= (2x)(2xโˆ’3) How do you find (g โˆ˜ f)(โˆ’2 + x) given g(x) = 2x โˆ’ 2 and f (x) = x2 + 3x 2x2 โˆ’2xโˆ’6 Explanation: The first step is Find the values of x in each of the following: (i)25x รท2x = 5โˆš220. (ii)(23)4 = (22)x. (iii)(3 5)x(5 3)2x = 125 27. (iv)5xโˆ’2 ร—32xโˆ’3 =135. (v)2xโˆ’7 ร—5xโˆ’4 = 1250. (vi)(3โˆš4)2x+1 2 = 1 32. (vii)52x+3 = 1. (viii) (13)โˆšx = 44 โˆ’34 โˆ’6. 2 x 1 = 2: 2 x 2 = 4: 2 x 3 = 6: 2 x 4 = 8: 2 x 5 = 10: 2 x 6 = 12: 2 x 7 = 14: 2 x 8 = 16: 2 x 9 = 18: 2 x 10 = 20: 2 x 11 = 22: 2 x 12 = 24: 2 x 13 = 26: 2 x 14 = 28: 2 x 15 = 30: 2 x 16 = 32: 2 x 17 = 34: 2 x 18 = 36: 2 x 19 = 38: 2 x 20 = 40 Find the Roots (Zeros) f(x)=x^3-2x^2+1. Step 1. Set equal to . Step 2. Solve for . Tap for more steps Step 2.1. Factor using the rational roots test. Tap for more steps Step 2.1.1. If a polynomial function has integer coefficients, then every rational zero will have the form where is a factor of the constant and is a factor of the leading If 4 = x + 2 then x + 2 = 4. If x + 3 = 2x - 5 then 2x - 5 = x + 3. If d = rt then rt = d. There may be several different ways to apply the addition property above. Sometimes one method is better than another, and in some cases, the symmetric property of equality is also helpful. Example 4 Solve 2x = 3x - 9. (1) .

5 2x 3 x 6 5